Prove that: 
(1 + tanΘ)^2 + (1 + cotΘ)^2 = (secΘ + cosecΘ)^2
Answer:




    The question is very much easy to solve if you know these basic things:

    (a +b)² = a² + 2ab + b²

    And

    1 + tan²x = sec²x
    i.e. sec²x - tan²x = 1

    Also

    1 + cot²x = cosec²x
    i.e. cosec²x - cot²x = 1

    And
     tanx = sinx / cosx
     Cotx = cosx/ sinx

    Now, just see the image upside and you can visualize the answer.

    Therefore, this is the process how you solve the given trigonometric identity,
    (1 + tanΘ)^2 + (1 + cotΘ)^2 = (secΘ + cosecΘ)^2, in Trigonometry of Mathematics.

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