If 3sinΘ +4cosΘ =5, show that: sinΘ = 3/5.

Answer:



Solving these questions are easy.
You have two different Trigonometric ratios on the same sides.
First step we need to do is put these two different Trigonometric ratios in two different sides of the equal to sign.
Then square both sides.

Then we need to change the given equation into quadratic equation. Viz. ax²+bx+c=0

Now, to do this we need to have all the terms common.
We know, cos²x = 1 - sin²x

So we will change the given cos² as the identity.


And we will get the quadratic equation. Using the formula of quadratic equation, we can get the value of sinΘ which is equal to 3/5.

So, this is how you prove the Trigonometric Values of the above-mentioned questions of Trigonometry.

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