Prove that: sec^4 α - 1 = 2 tan^2 α + tan^4 α
Answer:
We need to analyze the LHS of the given question.
We have a^2 - b^2 which can be expanded as (a+b) ( a-b) which we did in the process.
Using identity: sec^2 x - tan^2 x = 1
And sec^2 x = 1 + tan^2 x
We solved the above question and proved that the LHS is equal to the RHS.
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