Prove that: 
(sinΘ - cosΘ + 1) (sinΘ + cosΘ - 1) = secΘ + tanΘ

Answer:


The process I used to solve this question is simple! I rationalized the denominator. But for easiness, to open the formula, I took the sign common in between the numerator and denominator as you can see in the image.

Then when we rationalize,we have to open the formula of (a-b)^2 and a^2 - b^2

Once we do this, we get some we get sin^2 x + cos^2 x in numerator which we can write as 1.

Then we have to take the terms common and then cancel the equal terms of the numerator and denominator.

Then we apply simple mathematics to solve the question and prove that the LHS is equal to the RHS.

This way you can solve the given trigonometric identity of Trigonometry in mathematics.

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