Prove that: sin5Θ -sin3Θ +sin2Θ = 4sinΘ.cos3Θ/2.cos5Θ/2 
 Answer:
So, to solve this type of questions you need to understand the given formula of Trigonometry. Here, it's not exactly compound angles but yeah, you can term them as compound angles.

Also, sin2A = 2 sinA.cosA

Therefore, with all the above mentioned formula in mind, we can easily solve these types of Trigonometric questions. But, another thing to keep in mind is how do you take common between the terms. Be sincere when you are taking the common terms.

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