Prove that: cos 15° . sin 75° = (2+√3)/4 | SciPiPupil

Prove that: cos 15° . sin 75° = $\dfrac{2+\sqrt{3}}{4}$ | SciPiPupil

This is a class 10 Question From Trigonometric Identities chapter of Unit Trigonometry. All the steps for the solutions are mentioned as hint. 

Solution:

In this solution,

We have used the following trigonometric ratios obtained by the transformation of existing t-ratios.

cosA.sinB = sin(A+B) - sin(A-B)

Also,

We have used the following values of trigonometric ratios:

sin 90° = 1

sin 60° = $\dfrac{\sqrt{3}}{2}$

Related Notes:

Link: Introduction To Trigonometry

Link: Values of Trigonometric Ratios

Link: Compound Angles

See all the solutions of Trigonometric Identities in this page. 

Question: Prove that: cos 15° . sin 75° = (2+√3)/4 | SciPiPupil

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