Question: Rationalize the denominators and simplify: $\dfrac{1}{√3 -2}$
Solution:
Given,
$= \dfrac{1}{√3 - 2}$
$= \dfrac{1}{√3 -2} × \dfrac{√3 +2}{√3 +2}$
$= \dfrac{1(√3+2)}{(√3}² - 2²}$
$= \dfrac{√3 + 2}{3 -4}$
$= \dfrac{√3 +2}{-1}$
$= - (√3 +2)$
$= -√3 - 2$
= Answer
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