Question: Solve: 4^{2x-1} = 2^{x+1}
Solution:
Given,
4^{2x-1} = 2^{x+1}
or, \left ( 2^2 \right)^{2x-1} = 2^{x+1}
or, 2^{2(2x-1)} = 2^{x+1}
or, 2^{4x -2} = 2^{x+1}
or, 4x -2 = x +1
or, 4x -x = 1 +2
or, 3x = 3
or, \dfrac{3x}{3} = \dfrac{3}{3}
\therefore, x = 1
= Answer
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