Question: Solve: 4^{2x-1} = 2^{x+1}

Solution:
Given,

4^{2x-1} = 2^{x+1}

or, \left ( 2^2 \right)^{2x-1} = 2^{x+1}

or, 2^{2(2x-1)} = 2^{x+1}

or, 2^{4x -2} = 2^{x+1}

or, 4x -2 = x +1

or, 4x -x = 1 +2

or, 3x = 3

or, \dfrac{3x}{3} = \dfrac{3}{3}

\therefore, x = 1
= Answer


Related Notes and Solutions:

Here is the website link to the notes of Indices.

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