7^{2x+1} + 5^{2x-1} = 7/5 | Indices - Solve | SciPiPupil

Question: Solve: $7^{2x+1} + 5^{2x-1} = \dfrac{7}{5}$

Solution:

Given,

$7^{2x+1} + 5^{2x-1} = \dfrac{7}{5}$

$or, 7^{2x+1} + 5^{2x-1} = \dfrac{7}{5}$

$or, 7^{2x} × 7^1 × 5^{2x} × 5^{-1} = \dfrac{7}{5}$

$or, (35)^{2x} × 7 × \dfrac{1}{5} = \dfrac{7}5}$

$or, (35)^{2x} × \dfrac{7 × 5}{5 × 7} = \dfrac{ 7 ×5}{5×7}$

$or, 35^{2x} = 1$

$or, 35^{2x} = 35^0$

$or, 2x = 0$

$\therefore x = 0$

= Answer

Related Notes and Solutions:

Here is the website link to the notes of Indices.

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