Question: Simplify: \dfrac{a+2}{a² +a -2} +\dfrac{3}{a² -1}
Solution:
Given,
= \dfrac{a+2}{a² +a -2} +\dfrac{3}{a² -1}
= \dfrac{a+2}{a² +(2-1)a -2} +\dfrac{3}{a² -1}
= \dfrac{a +2}{a² +2a -a -2} +\dfrac{3}{a² -1}
= \dfrac{a +2}{a(a +2) -1(a+2)} +\dfrac{3}{a² -1}
= \dfrac{a+2}{(a-1)(a+2)} +\dfrac{3}{a² -1}
= \dfrac{1}{a -1} +\dfrac{3}{(a+1)(a-1)}
= \dfrac{1(a+1) +3}{(a-1)(a+1)}
= \dfrac{a +1 +3}{a²-1}
= \dfrac{a +4}{a² -1}
= Answer
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