Question: Compute mean deviation and its coefficient from mean of following frequency data:
Mid Wages (RS.) | 20 | 25 | 30 | 35 | 40 |
No. of workers | 2 | 5 | 6 | 5 | 2 |
Solution:
Arranging data in a table,
Mid Value(x) | Frequency (f) | fx | |x-x̄| | f|x-x̄| |
20 | 2 | 40 | 10 | 20 |
25 | 5 | 125 | 5 | 25 |
30 | 6 | 180 | 0 | 0 |
35 | 5 | 175 | 5 | 25 |
40 | 2 | 80 | 10 | 20 |
N=20 | $\sum$|x-x̄| = 600 | $\sum$fx|x-x̄| = 90 |
Now,
Mean (x̄) =$\dfrac{\sum fx}{N}$
Mean (x̄) =$\dfrac{\sum fx}{N}$
$= \dfrac{600}{20}$
$= 30$
And,
Mean Deviation from Mean (M.D.) = $\dfrac{\sum f|x-x̄|}{N}$
$= \dfrac{90}{20}$
$= 4.5$
Also,
Coefficient of M.D. = $\dfrac{M.D.}{x̄}$
$= \dfrac{4.5}{30}$
$= 0.15$
Hence, the required mean deviation about the mean of the given data is 4.5 and coefficient of mean deviation is 0.15.
Related Notes and Solutions:
Here is the website link to the notes of Statistics of Class 10.
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