Question: Find the mean deviation about the mean for the following data:
Mark | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
Number Of Students | 6 | 8 | 14 | 16 | 4 | 2 |
Solution:
Arranging data in a table,
Marks | Frequency (f) | Mid Value(x) | fx | |x-x̄| | f|x-x̄| |
0-10 | 6 | 5 | 30 | 22 | 132 |
10-20 | 8 | 15 | 120 | 12 | 36 |
20-30 | 14 | 25 | 350 | 2 | 28 |
30-40 | 16 | 35 | 560 | 8 | 128 |
40-50 | 4 | 45 | 180 | 18 | 72 |
50-60 | 2 | 55 | 110 | 28 | 56 |
N= 50 | $\sum$fx = 1350 | $\sum$f|x-x̄| = 512 |
Mean (x̄) =$\dfrac{\sum fx}{N}$
$= \dfrac{1350}{50}$
$= 27$
And,
Mean Deviation from Mean (M.D.) = $\dfrac{\sum f|x-x̄|}{N}$
$= \dfrac{512}{50}$
$= 10.24$
Hence, the required mean deviation about the mean of the given data is 10.24.
Related Notes and Solutions:
Here is the website link to the notes of Statistics of Class 10.
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