Question: Find the mean deviation about the mean for the following data:

Mark 0-1010-2020-30 30-40 40-5050-60
Number Of Students 6814 16 42


Solution:

Arranging data in a table,


MarksFrequency
(f)
Mid
Value(x)
fx|x-x̄|f|x-x̄|
0-10 653022132
10-20 8151201236
20-30 1425350228
30-40 16355608128
40-50 4451801872
50-60 2551102856
N= 50\sumfx
= 1350

\sumf|x-x̄|
= 512
Now,
Mean () =\dfrac{\sum fx}{N}

= \dfrac{1350}{50}

= 27

And,

Mean Deviation from Mean (M.D.) = \dfrac{\sum f|x-x̄|}{N}

= \dfrac{512}{50}

= 10.24

Hence, the required mean deviation about the mean of the given data is 10.24.

Related Notes and Solutions:

Here is the website link to the notes of Statistics of Class 10.

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