Question: Find the mean deviation about the mean for the following data:
Mark | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency | 2 | 3 | 6 | 5 | 4 |
Solution:
Arranging data in a table,
Marks | Frequency (f) | Mid Value(x) | fx | |x-x̄| | f|x-x̄| |
0-10 | 2 | 5 | 10 | 23 | 46 |
10-20 | 3 | 15 | 45 | 13 | 39 |
20-30 | 6 | 25 | 150 | 3 | 18 |
30-40 | 5 | 35 | 175 | 7 | 35 |
40-50 | 4 | 45 | 180 | 17 | 68 |
N= 20 | $\sum$fx = 560 | $\sum$f|x-x̄| = 206 |
Mean (x̄) =$\dfrac{\sum fx}{N}$
$= \dfrac{560}{20}$
$= 28$
And,
Mean Deviation from Mean (M.D.) = $\dfrac{\sum f|x-x̄|}{N}$
$= \dfrac{206}{20}$
$= 10.30$
Also,
Coefficient of M.D. = $\dfrac{M.D.}{x̄}$
$= \dfrac{10.30}{20}$
$= 0.37$
Hence, the required mean deviation about the mean of the given data is 10.30 and coefficient of mean deviation is 0.37.
Related Notes and Solutions:
Here is the website link to the notes of Statistics of Class 10.
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