Question: If $x= y^z , y=z^x and z=x^y$, prove that: xyz = 1$
Solution:
Given,
$x= y^z , y=z^x and z=x^y$
To prove: $xyz = 1$
We know,
$x = y^z$
$or, x = (z^x)^z$
$or, x = z^{xz}$
$or, x = (x^y)^{xz}$
$or, x = x^{xyz}$
$or, x^1 = x^{xyz}$
$or, 1 = xyz$
$\therefore xyz = 1$
#proved
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