Question: In the adjoining figure, ABCD is a square. If the equation of its diagonal is x-3y=2, find the equations of AB and BC.


Solution:

Given: ABCD is a square. BD is a diagonal.
We know, each angle in a square is 90° and diagonal bisects the right angle in a square. So, <ABD = <CBD = 45°

To find: equations of line AB and BC.

We have,

Equation of diagonal BD is x -3y = 2
slope of the line (m) = - \dfrac{coefficient of x}{coefficient of y}
= - \dfrac{1}{-3}
= \dfrac{1}{3}
So, slope of BD (m) = 1/3

Using the formula of angle between two lines;

tan \theta = +_- \left ( \dfrac{m_1 -m_2}{1 +m_1m_2} \right)

Taking m_1 = m = \dfrac{1}{3} \; and \;\theta = 45°

tan 45° = +_- \left ( \dfrac{\frac{1}{3} -m_2}{1 +\frac{1}{3}m_2} \right)

Taking positive sign;
tan 45° = \dfrac{\frac{1}{3} -m_2}{1 +\frac{1}{3}m_2}

1 = \dfrac{\frac{1 -3m_2}{3}}{\frac{3 +m_2}{2}}

1 = \dfrac{1 - 3 m_2}{3 + m_2}

3+m_2 = 1 -3m_2

or, 4m_2 = -2

\therefore, m_2 = -\frac{1}{2}
So, slope of line AB = - (1/2)


Taking negative sign;
or, tan 45° =-\left( \dfrac{\frac{1}{3} -m_2}{1 +\frac{1}{3}m_2} \right)

or, - 1 = \dfrac{\frac{1 -3m_2}{3}}{\frac{3 +m_2}{2}}

or, -1 (3+ m_2) = 1 - 3 m_2

-3-m_2 = 1- 3m_2

2m_2 = 4

\therefore, m_2 = 2
So, slope of line BC = 2

Solving the equation of diagonal BD: x-3y=2
Taking testing points (5,1) = (x,y)
or, 5 - 3(1) = 2
or, 5 - 2 = 2
So, 2 = 2 which is true.

It means that point (5,1) lies on the diagonal and is the coordinate of one of the vertex.

Now,

Equation of line AB when (x_1, y_1) = (5,1) \; and \; m = - \frac{1}{2}
or, (y - y_1) = m(x - x_1)
or, (y - 1) = - \frac{1}{2} (x -5)
or, 2(y -1) = -x +5
or, 2y -2 = -x +5
or, x -2y = -5-2
\therefore, x -2y = -7 is the required equation of line AB.

Equation of line BC when (x_1, y_1) = (5,1) \; and \; m = 2
or, (y -y_1) = m(x -x_1)
or, (y -1) = 2(x -5)
or, (y -1) = 2x -10
or, 2x -y = 10 -1
\therefore, 2x -y = 9 is the required equation of line BC.

Hence,
Required equations are (x -2y = 7) and (2x -y = 9).


Related Notes and Solutions:

Here is the website link to all the important formulae of Coordinate Geometry of Class 10.

#SciPiPupil