Question: Solve: \sqrt[4]{2x -1} - 2 = 1

Solution:
Given,

\sqrt[4]{2x -1} - 2 = 1

or, \sqrt[4]{2x -1} = 1 +2

or, \sqrt[4]{2x -1} = 3

[ Raise both sides to the power of 4 ]

or, (\sqrt[4]{2x -1}}^4 = 3^4

or, 2x -1 = 81

or, 2x = 81 +1

or, x = \dfrac{82}{2}

\therefore x = 41