Question: Solve: $\sqrt[4]{2x -1} - 2 = 1$

Solution:
Given,

$\sqrt[4]{2x -1} - 2 = 1$

$or, \sqrt[4]{2x -1} = 1 +2$

$or, \sqrt[4]{2x -1} = 3$

[ Raise both sides to the power of 4 ]

$or, (\sqrt[4]{2x -1}}^4 = 3^4$

$or, 2x -1 = 81$

$or, 2x = 81 +1$

$or, x = \dfrac{82}{2}$

$\therefore x = 41$