Question: Solve: 2x +1 = \sqrt{4x²+3x +6}

Solution:
Given,

2x +1 = \sqrt{4x²+3x +6}

[ squaring both sides ]

or, (2x +1)² = (\sqrt{4x²+3x+6})²

or, (2x)² + 2×2x×1 +1² = 4x²+3x+6

or, 4x² +4x +1 = 4x² + 3x +6

or, 4x²-4x²+4x -3x = 6-1

\therefore x = 5