Question: Prove that the lines represented by the following equation is coincident: 2x² +12xy +18y² = 0.
Solution:
Given,
Equation of line is 2x² +12xy +18y² = 0
or, 2x² + 2×6xy + 18y² = 0 - (i)
Comparing equation (i) with ax² + 2hxy + by²=0, we get,
a = 2, h = 6, and b = 18
We know, when two lines are coincident, h² = ab,
or, h² = ab
or, 6² = 2×18
or, 36 = 36 which is true.
Therefore, it is proved that the lines represented by the given equation is coincident.
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