Question: Solve: \sqrt{2x +7} = x +2
Solution:
Given,
\sqrt{2x +7} = x +2
[ Squaring both sides ]
or, (\sqrt{2x +7})^2 = (x +2)^2
or, 2x +7 = x^2 + 2×x×2 + 2^2
or, 2x +7 = x^2 +4x + 4
or, x^2 + 4x -2x +4 -7 = 0
or, x^2 +2x -3 = 0
or, x^2 +(3-1)x +3= 0
or, x^2 + 3x -x +3 = 0
or, x(x +3) -1(x +3) = 0
or, (x -1)(x +3) = 0
Either,
(x -1) = 0
\therefore x = 1
Or,
(x +3) = 0
Now,
Substituting x = 1 in the given equation:
\sqrt{2×1 + 7} = 1+2
or, \sqrt{2+7} = 3
or, \sqrt{9} = 3
$or, 3 = 3 which is true.
Again,
Substituting x = -3 in the given equation:
\sqrt{2×(-3) + 7} = -3 +2
or, \sqrt{-6+7} = -3 +2
or, \sqrt{1} = -1 which is false.
Hence, x = 1.
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