Question: Solve: \sqrt{3x -2} - 2 = 3

Solution:
Given,

\sqrt{3x -2} - 2 = 3

or, \sqrt{3x - 2} = 3+2

or, \sqrt{3x -2} = 5

[ Squaring both sides ]

or, ( sqrt{3x -2})^2 = 5^2

or, 3x -2 = 25

or, 3x = 25+2

or, 3x = 27

or, x = \dfrac{27}{3}

\therefore, x = 9