Question: Solve: $\sqrt{3x -2} - 2 = 3$

Solution:
Given,

$\sqrt{3x -2} - 2 = 3$

$or, \sqrt{3x - 2} = 3+2$

$or, \sqrt{3x -2} = 5$

[ Squaring both sides ]

$or, ( sqrt{3x -2})^2 = 5^2$

$or, 3x -2 = 25$

$or, 3x = 25+2$

$or, 3x = 27$

$or, x = \dfrac{27}{3}$

$\therefore, x = 9$