Question: Solve: $\sqrt{4x -3} = 3$

Solution:
Given,

$\sqrt{4x -3} = 3$

[ Squaring both sides ]

$or, (\sqrt{4x -3})^2 = 3^2$

$or, 4x -3 = 9$

$or, 4x = 9+3$

$or, x = \dfrac{12}{4}$

$\therefore x = 3$