Question: Solve \sqrt[3]{7x +11} = \sqrt[3]{3x +5}

Solution:
Given,

\sqrt[3]{7x +11} = \sqrt[3]{3x +5}

[ Cubing both sides ]

or, (\sqrt[3]{7x +11})^3 = (\sqrt[3]{3x +5})^3

or, 7x +11 = 3x +5

or, 7x -3x = 5-11

or, 4x = -6

or, x = -\dfrac{6}{4}

\therefore x = - \dfrac{3}{2}