Question: Solve \sqrt[3]{7x +11} = \sqrt[3]{3x +5}
Solution:
Given,
\sqrt[3]{7x +11} = \sqrt[3]{3x +5}
[ Cubing both sides ]
or, (\sqrt[3]{7x +11})^3 = (\sqrt[3]{3x +5})^3
or, 7x +11 = 3x +5
or, 7x -3x = 5-11
or, 4x = -6
or, x = -\dfrac{6}{4}
\therefore x = - \dfrac{3}{2}
0 Comments
You can let us know your questions in the comments section as well.