Question: Find the standard deviation of the following data:
Class Interval | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequency | 5 | 8 | 15 | 16 | 6 |
Solution:
[Comment: assumed mean is easier way to perform standard deviation, so we use Assumed Mean method]
Taking Assumed Mean (A) = 25
Arranging the given data in a table;
Marks | Frequency (f) | Mid-value (m) | d(x-25) | d² | fd | fd² |
0-10 | 5 | 5 | -20 | 400 | -100 | 2000 |
10-20 | 8 | 15 | -10 | 100 | -80 | 800 |
20-30 | 15 | 25 | 0 | 0 | 0 | 0 |
30-40 | 16 | 35 | 10 | 100 | 160 | 1600 |
40-50 | 6 | 45 | 20 | 400 | 120 | 2400 |
N = 50 | $\sum$fd = 100 | $\sum$fd² =6800 |
Now,
Standard Deviation ($\sigma$) = $\sqrt{ \dfrac{\sum fd²}{N} - \left ( \dfrac{\sum fd}{N} \right )}^2$
$= \sqrt{ \dfrac{6800}{50} - \left ( \dfrac{100}{50} \right )}^2$
$= \sqrt{ 136 - (2)²}$
$= \sqrt{136 - 4}$
$= \sqrt{132}$
$= 11.48$
Hence, the required standard deviation of the give data is 11.48.
How to take Assumed Mean?
In this method, the mean is taken as the mid-value of the mid-class from the given data. Here, mid term is mid-class is 20-30 and the mid-value is 25.
Related Notes and Solutions:
Here is the website link to the notes of Statistics of Class 10.
#SciPiPupil
2 Comments
Hello I suggest you to put pictures instead of d frac and such symbols. We are students and do not understand such symbols.
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