Question: Find the standard deviation of the following data:


Class Interval25-3535-4545-5555-6565-75
Frequency54673

Solution:

[Comment: assumed mean is easier way to perform standard deviation, so we use Assumed Mean method]

Taking Assumed Mean (A) = 50

Arranging the given data in a table;


MarksFrequency
(f)
Mid-value
(m)
d(x-50)fdfd²
25-35530-20400-1002000
35-45440-10100-40400
45-556500000
55-657601010070700
65-7537020400601200
N = 25$\sum$fd
= -10
$\sum$fd²
=4300

Now,

Standard Deviation ($\sigma$) = $\sqrt{ \dfrac{\sum fd²}{N} - \left ( \dfrac{\sum fd}{N} \right )}^2$

$= \sqrt{ \dfrac{4300}{25} - \left ( \dfrac{-10}{25} \right )}^2$

$= \sqrt{ 172 - (-0.4)²}$

$= \sqrt{172- 0.16}$

$= \sqrt{171.84}$

$= 13.108$

$= 13.11$

Hence, the required standard deviation of the give data is 13.08.


How to take Assumed Mean?

In this method, the mean is taken as the mid-value of the mid-class from the given data. Here, mid term is mid-class is 45-55 and the mid-value is 50.


Related Notes and Solutions:

Here is the website link to the notes of Statistics of Class 10.

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