Question: Find the standard deviation:
Class Interval | 0-10 | 0-20 | 0-30 | 0-40 | 0-50 |
Frequency | 2 | 5 | 10 | 13 | 15 |
Solution:
[Comment: assumed mean is easier way to perform standard deviation, so we use Assumed Mean method]
Taking Assumed Mean (A) = 25
Arranging the given data in a table;
X | f | Mid-value (m) | d(x-25) | d² | fd | fd² |
0-10 | 2 | 5 | -20 | 400 | -40 | 800 |
0-20 (10-20) | 3 | 15 | -10 | 100 | -30 | 300 |
0-30 (20-30) | 5 | 25 | 0 | 0 | 0 | 0 |
0-40 (30-40) | 3 | 35 | 10 | 100 | 30 | 300 |
0-50 (40-50) | 2 | 45 | 20 | 400 | 40 | 800 |
N = 15 | $\sum$fd = 0 | $\sum$fd² =2200 |
Now,
Standard Deviation ($\sigma$) = $\sqrt{ \dfrac{\sum fd²}{N} - \left ( \dfrac{\sum fd}{N} \right )}^2$
$= \sqrt{ \dfrac{2200}{15} - \left ( \dfrac{-0}{15} \right )}^2$
$= \sqrt{ 146.66}$
$= 12.11$
Hence, the required standard deviation of the give data is 12.11.
How to take Assumed Mean?
In this method, the mean is taken as the mid-value of the mid-class from the given data. Here, mid term is mid-class is 20-30 and the mid-value is 25.
Related Notes and Solutions:
Here is the website link to the notes of Statistics of Class 10.
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