Question: Find the standard deviation using actual mean.


X 0-1010-2020-30 30-4040-5050-60
f 4610 2064

Solution:

Using actual mean,

Arranging the data in a table,


Xfmfmd|x-31|fd²
0-104520 266762704
10-2061590 162561536
20-301025250 -636360
30-402035700 416320
40-50645270 141961176
50-60455220 245762304
N=50
$\sum$fm
 = 1550
$\sum$fd²=8400
Now,

Mean = $\dfrac{\sum fm}{N}$

$= \dfrac{1550}{50}$

$= 31$
 

Standard Deviation ($\sigma$) = $ \sqrt{ \dfrac{\sum fd²}{N} }$

$= \sqrt{ \dfrac{8400}{50} }$

$= \sqrt{168}$

$= 12.96$

Hence, the required standard deviation using actual mean of the given data is 12.96.

Related Notes and Solutions:

Here is the website link to the notes of Statistics of Class 10.

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