Question: From the following data, find the standard deviation and coefficient of variation.
Class Interval | 0-10 | 0-20 | 0-30 | 0-40 | 0-50 |
Frequency | 8 | 18 | 30 | 38 | 40 |
Solution:
Using actual mean,
[We have, interval between two classes is 10.
To get the frequency, subtract the give frequency of the respective class from one step higher class.]
Arranging the data in a table,
X | f | m | fm | d|x-21.5| | d² | fd² |
0-10 | 8 | 5 | 40 | 16.5 | 272.25 | 2178 |
0-20 (10-20) | 10 | 15 | 150 | 6.5 | 42.25 | 422.5 |
0-30 (20-30) | 12 | 25 | 300 | 3.5 | 12.25 | 147 |
0-40 (30-40) | 8 | 35 | 280 | 13.5 | 182.25 | 1458 |
0-50 (40-50) | 2 | 45 | 90 | 23.5 | 552.25 | 1104.5 |
N=40 | $\sum$fm = 860 | $\sum$fd² =5310 |
Mean = $\dfrac{\sum fm}{N}$
$= \dfrac{860}{40}$
$= 21.5$
Standard Deviation ($\sigma$) = $ \sqrt{ \dfrac{\sum fd²}{N} }$
$= \sqrt{ \dfrac{5310}{40} }$
$= \sqrt{132.75}$
$= 11.52$
And,
Coefficient of Variation = $\dfrac{\sigma}{mean} × 100%$
$= \dfrac{11.52}{21.5} × 100%$
$= 0.5358 × 100%$
$= 53.58%$
Hence, the required standard deviation using actual mean of the given data is 11.52 and the coefficient of variation is 53.58%.
Related Notes and Solutions:
Here is the website link to the notes of Statistics of Class 10.
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