Question: In a city, the taxi charges consists of two types of a charges: a fixed charge together with the charge for the distance covered. If a person travels 10km, he pays Rs 180 and for travelling 12km, he pays Rs 210. Find the fixed charges and the rate of charge per km.
Solution:
Let the fixed charge of the taxi in that city be Rs x. And, the charge per km be Rs y.
According to the question,
Condition I,
A person travels 10km and he pays Rs 180.
or, x + 10y = 180
or, x = 180 - 10y - (i)
Condition II,
When he travels 12km, he pays Rs 210.
or, x + 12y = 210 - (ii)
Put the value of x from equation (i) in equation (ii), we get,
or, 180 - 10y +12y = 210
or, 2y = 210 -180
or, 2y = 30
or, 2×y = 2×15
\therefore y = 15
And,
Put the value of y in equation (i), we get,
or, x = 180 - 10×15
or, x = 180 - 150
\therefore x = 30
So, (x,y) = (30,15)
Hence, the required fixed charge of taxi in that city is Rs 30 and the rate of charge per km is Rs 15.
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