Question: Janak started his bicycle journey from Kohalpur to Dhangadhi at 6:00 a.m. with an average speed of 20 km/hr. Two hours later Ganesh also started his journey from Kohalpur to Dhangadhi with an average speed of 30 km/hr. At what time would they meet each other if both of them maintain non-stop journey.

Solution:

Let the time taken by Janak and Ganesh to meet each other be x hours.

Since Ganesh started after two hours, he meets Jamla after (x-2) hours.

Now, the distance travelled by Janka in x hours = 20x km

Also, the distance travelled by Ganesh in (x-2) hours = 30(x-2) km.

When they travelled the equal distance, they meet each other.
$or, 20x = 30(x -2)$
$or, 20x = 30x -60$
$or, 60 = 30x -20x$
$or, 60 = 10x$
$or, x = \frac{60}{10}$
$\therefore x = 6$

Hence, they meet each other after 6 hours.

Here, x=6. This means he they meet each other after 6 hours from 6 a.m. So, they met each other after 6:am +6 hours = 12p.m.