Question: Show that the equations x²-2xy+y²-2x+2y=0 represents two straight lines which are parallel to each other.
Solution:
Given,
Single equation of two straight lines is x² -2xy +y² -2x +2y = 0
or, x² -2xy +y² -2x +2y = 0
or, (x)² -2.x.y + (y)² - 2(x -y) = 0
or, (x -y)² - 2(x -y)= 0
or, (x -y)(x -y) -2(x-y) = 0
or, (x-y) (x -y-2) = 0
So, the two separate equations of straight lines are x -y = 0 and x -y -2 = 0.
For line 1 (x -y = 0$),
Slope (m_1) = -\frac{coefficient \; of \;x}{coefficient \; of \; y}
= - \frac{1}{-1}
= 1
For line 2 (x -y -2 = 0),
Slope (m_2) = - \frac{coefficient \; of x }{ coefficient \; of \; y}
= - \frac{1}{-1}
= 1
For line lines to be parallel, their slopes should be equal.
or, m_1 = m_2
or, 1 = 1 which is true.
Therefore, it is proved that the two separate equations of lines represented by the given single equation are parallel to each other.
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