Question: Solve: \dfrac{x -25}{√x -5} = 9
Solution:
Given,
\dfrac{x -25}{√x -5} = 9
or, \dfrac{(√x)^2 - (5)^2}{√x -5} = 9
or, \dfrac{(√x +5)(√x -5)}{(√x -5)} = 9
or, √x +5 = 9
or, √x = 9-5
or, √x = 4
[ Squaring both sides ]
or, (√x)^2 = 4^2
\therefore x = 16
= Answer
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