Question: Solve: \dfrac{x -25}{√x -5} = 9

Solution:
Given,
\dfrac{x -25}{√x -5} = 9

or, \dfrac{(√x)^2 - (5)^2}{√x -5} = 9

or, \dfrac{(√x +5)(√x -5)}{(√x -5)} = 9

or, √x +5 = 9

or, √x = 9-5

or, √x = 4

[ Squaring both sides ]

or, (√x)^2 = 4^2

\therefore x = 16
= Answer