Question: Solve: \dfrac{√x -4}{√x} = \dfrac{3}{7}

Solution:
Given,

\dfrac{√x -4}{√x} = \dfrac{3}{7}

or, 7(√x -4) = 3√x

or, 7√x - 28 = 3√x

or, 7√x - 3√x = 28

or, 4√x = 28

or, √x = \dfrac{28}{4}

or, √x = 7

[ Squaring both sides ]

or, (√x)^2 = 7^2

\therefore x = 49
= Answer