Question: Solve: $\dfrac{√x -4}{√x} = \dfrac{3}{7}$

Solution:
Given,

$\dfrac{√x -4}{√x} = \dfrac{3}{7}$

$or, 7(√x -4) = 3√x$

$or, 7√x - 28 = 3√x$

$or, 7√x - 3√x = 28$

$or, 4√x = 28$

$or, √x = \dfrac{28}{4}$

$or, √x = 7$

[ Squaring both sides ]

$or, (√x)^2 = 7^2$

$\therefore x = 49$
= Answer