Question: Solve the pair of the following simultaneous equation: y=x-2 and x+y=4.


Solution:
Given,

Equation (i) is y = x-2

Equation (ii) is x+y=4

Put value or y from equation (i) in equation (ii), we get,

or, x + (x-2) = 4

or, x + x-2 = 4

or, 2x = 4+2

or, 2x = 6

or, x = \dfrac{6}{2}

\therefore x = 3

Now,

Put value of x in equation (i), we get,

y = 3-2

\therefore y = 1

Hence, (x,y) = (3,1).

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