Question: Solve the pair of the following simultaneous equation: y=x-2 and x+y=4.
Solution:
Given,
Equation (i) is y = x-2
Equation (ii) is x+y=4
Put value or y from equation (i) in equation (ii), we get,
or, x + (x-2) = 4
or, x + x-2 = 4
or, 2x = 4+2
or, 2x = 6
or, x = \dfrac{6}{2}
\therefore x = 3
Now,
Put value of x in equation (i), we get,
y = 3-2
\therefore y = 1
Hence, (x,y) = (3,1).
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