Question: Solve the pair of the following simultaneous equation: $y=x-2$ and $x+y=4$.


Solution:
Given,

Equation (i) is $y = x-2$

Equation (ii) is $x+y=4$

Put value or y from equation (i) in equation (ii), we get,

$or, x + (x-2) = 4$

$or, x + x-2 = 4$

$or, 2x = 4+2$

$or, 2x = 6$

$or, x = \dfrac{6}{2}$

$\therefore x = 3$

Now,

Put value of x in equation (i), we get,

$y = 3-2$

$\therefore y = 1$

Hence, (x,y) = (3,1).

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