In this page, you can find the complete solutions of the first exercise of  Circle chapter from Basic Mathematics Grade XI book published and distributed by Sukunda Pustak Bhawan.

In the above-mentioned book, circle is the 11th chapter and has two exercises only. Out of which, this is the solution of the first exercise.

Check: Basic Mathematics Grade 11 (Sukunda Publication) Guide:
Grade 11 Basic Mathematics by Sukunda Pustak Vawan Notes and Solutions | Nepal

 

Quick Revision:

Circle is a closed curved such that the straight distance from its centre to any point on the circumference is always a common constant and that common constant is called its radius.

Here are few formulae of circle:
  • When the circle has its centre at origin, then the equation of circle is given by $x^2 + y^2 = r^2$
  • When the circle has its centre at point (h,k), then the equation of circle is given by $(x-h)^2 + (y-k)^2 = r^2$
  • When the circle passes through the origin, then the equation of circle is given by $(x-h)^2 + (y-k)^2 = h^2 + k^2$
  • The general equation of a circle is $x^2 + y^2 + 2gx + 2fy + c = 0$
  • The equation of circle touching x-axis is $(x-h)^2 + (y-k)^2 = k^2$
  • The equation of circle touching y-axis is $(x-h)^2 + (y-k)^2 = h^2$
  • The equation of circle touching both axes is $(x-h)^2 + (y-h)^2 = h^2$ or $(x-k)^2 + (y-k)^2 = k^2$ or $(x-r)^2 + (y-r)^2 = r^2$.
  • The equation of circle with the end points of a diameter as $(x_1,y_1)$ and $(x_2,y_2)$ is $(x-x_1)(x-x_2) + (y-y_1)(y-y_2) = 0$
  • The perpendicular distance between a point $(x_1,y_1)$ and a straight line $Ax+By+C=0$ is given by $\left | \dfrac{Ax_1 + By_1 + C}{\sqrt{A^2 + B^2}} \right |$

Disclaimer:

Answers mentioned here are not solved by teachers. These are the solutions written by a student of Grade 11. Answers are all correct. However, the language or process of solving the questions might be informal and in examinations, you might have to add little more language and show more calculations than what has been done here. So, we highly encourage you to view these solutions as guide rather than just copying everything mentioned here.



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About the Textbook:

Name: Basic Mathematics Grade XI
Author(s): D.R. Bajracharya | R.M. Shresththa | M.B. Singh | Y.R. Sthapit | B.C. Bajracharya
Publisher: Sukunda Pustak Bhawan (Bhotahity, Kathmandu)
Telephone: 5320379, 5353537
Price: 695 /- (2078 BS)