In this page, you can find the complete solutions of the first exercise
of Circle chapter from Basic Mathematics Grade XI book published and
distributed by Sukunda Pustak Bhawan.
In the above-mentioned book, circle is the 11th chapter and has two exercises
only. Out of which, this is the solution of the first exercise.
Check: Basic Mathematics Grade 11 (Sukunda Publication) Guide:
Grade 11 Basic Mathematics by Sukunda Pustak Vawan Notes and Solutions | Nepal
Quick Revision:
Circle is a closed curved such that the straight distance from its centre to
any point on the circumference is always a common constant and that common
constant is called its radius.
Here are few formulae of circle:
- When the circle has its centre at origin, then the equation of circle is given by $x^2 + y^2 = r^2$
- When the circle has its centre at point (h,k), then the equation of circle is given by $(x-h)^2 + (y-k)^2 = r^2$
- When the circle passes through the origin, then the equation of circle is given by $(x-h)^2 + (y-k)^2 = h^2 + k^2$
- The general equation of a circle is $x^2 + y^2 + 2gx + 2fy + c = 0$
- The equation of circle touching x-axis is $(x-h)^2 + (y-k)^2 = k^2$
- The equation of circle touching y-axis is $(x-h)^2 + (y-k)^2 = h^2$
- The equation of circle touching both axes is $(x-h)^2 + (y-h)^2 = h^2$ or $(x-k)^2 + (y-k)^2 = k^2$ or $(x-r)^2 + (y-r)^2 = r^2$.
- The equation of circle with the end points of a diameter as $(x_1,y_1)$ and $(x_2,y_2)$ is $(x-x_1)(x-x_2) + (y-y_1)(y-y_2) = 0$
- The perpendicular distance between a point $(x_1,y_1)$ and a straight line $Ax+By+C=0$ is given by $\left | \dfrac{Ax_1 + By_1 + C}{\sqrt{A^2 + B^2}} \right |$
Disclaimer:
Answers mentioned here are not solved by teachers. These are the solutions
written by a student of Grade 11. Answers are all correct. However, the
language or process of solving the questions might be informal and in
examinations, you might have to add little more language and show more
calculations than what has been done here. So, we highly encourage you to view
these solutions as guide rather than just copying everything mentioned here.
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About the Textbook:
Name: Basic Mathematics Grade XI
Author(s): D.R. Bajracharya | R.M. Shresththa | M.B. Singh | Y.R.
Sthapit | B.C. Bajracharya
Publisher: Sukunda Pustak Bhawan (Bhotahity, Kathmandu)
Telephone: 5320379, 5353537
Price: 695 /- (2078 BS)
Buy this book: Basic Mathematics : Grade XI – Sukunda Publication
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