Geometry is the easiest portion of Mathematics in Class 10, if you exclude the out theorem which comes for 5 marks. Other questions are very easy to tackle and aren't much tricky.

Geometry is asked in all Groups i.e. Group A, Group B, Group C, and Group D.

In Group A, it is asked for 1 mark (1 question).

In Group B, it is asked for 4 marks (2 questions).

In Group C, it is asked for 12 marks (3 questions).

In Group D, it is asked for 5 marks (1 question).

Let us move to the solutions of Circle from Geometry Chapter of Class 10.

Exercise 13.2

Creative Section



5 a) In the adjoining figure, O is the centre of the circle and PQ is the diamter. Show that angle PRQ is a right angle.

Class 10 - Geometry - Circle - Solved Exercises | vedanta Excel in Mathematics



5 b) In the given figure, O is the centre of the circ.e Prove that, angle POR = 2 ( angle PRQ + angle QPR).

Class 10 - Geometry - Circle - Solved Exercises | vedanta Excel in Mathematics



5 c) In the given figure, O is the centre of the circle. If arc.AC = arc.BC and BC is an angle bisector of angle ABO, prove that triangle ABO is an equilateral triangle.

Class 10 - Geometry - Circle - Solved Exercises | vedanta Excel in Mathematics



5 d) In the given figure, O is the centre of the cirlce, AB the diameter and arc(BC) = arc(CD). Prove that AD // OC.

Class 10 - Geometry - Circle - Solved Exercises and Theorem Proofs | vedanta Excel in Mathematics





5 e) In the adjoining figure, AB is the diameter. OC and OD are the radii where < BOC = < COD. Prove that AD // OC.

Class 10 - Geometry - Circle - Solved Exercises and Theorem Proofs | vedanta Excel in Mathematics



5 f) In the figure alongside, chords MN and RS of a circle intersect externally at X.
Prove that <MXR = (in degree) 1/2 (MR - NS).

Class 10 - Geometry - Circle - Solved Exercises and Theorem Proofs | vedanta Excel in Mathematics




5 g) In the given circle, chords DE and FG intersect within the circle at X. Prove that, <DXF = (in degre) 1/2 ( arc DF + arc GE).

Class 10 - Geometry - Circle - Solved Exercises and Theorem Proofs | vedanta Excel in Mathematics



5 h) In the given figure, O is the centre of a circle. C and D are two points on the cord AB. IF AC = BD and arc AM = arc BN, prove that < ACM = < BDN.

Class 10 - Geometry - Circle - Solved Exercises and Theorem Proofs | vedanta Excel in Mathematics


5 p) In the adjoining figure, POQ and ROT are two diamters of a circle with centre at O. If Q is the mid-point of the arc TQS and <QOR is obtuse, prove that PQ // RS.

Class 10 - Geometry - Circle - Solved Exercises and Theorem Proofs | vedanta Excel in Mathematics


8 a)
Class 10 - Geometry - Circle - Solved Exercises and Theorem Proofs | vedanta Excel in Mathematics

8 d)

Class 10 - Geometry - Circle - Solved Exercises and Theorem Proofs | vedanta Excel in Mathematics





About vedanta EXCEL in MATHEMATICS Book 10

Author: Hukum Pd. Dahal
Editor: Tara Bahadur Magar

Vanasthali, Kathmandu, Nepal
+977-10-4382404, 01-4362082
vedantapublication@gmail.com


About this page:


Class 10 - Geometry - Area of Triangles and Quadrilaterals- Solved Exercises | vedanta Excel in Mathematics is a collection of the solutions related to theorem proofs of figures related to the area of triangles and quadrilaterals of geometry chapter for Nepal's Secondary Education Examination (SEE) appearing students.

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