Question: Find the LCM between (a-3)², (a-9) and (a³+27).


Solution:

1st expression: (a-3)²
= (a-3)(a-3)

2nd expression: (a² -9)
= (a² - 3²)
= (a+3)(a-3)

3rd expression: (a³ +27)
= (a³ +3³)
= (a+3) (a² -3a +9)

Now,

Lowest Common Multiples (L.C.M.) = common factors * rest factors
= (a+3)(a-3) * (a-3)(a² -3a +9)
= (a-3)(a-3) * (a+3)(a² -3a +9)
= (a² -9)(a³ +27)

Related Notes and Solutions:

Here is the Website link to the guide of solving HCF and LCM.
Here are all solutions of LCM for Class 10.

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