Grade 11 Review of Composition and Resolution of Vectors Exercise 2 Solutions | Basic Mathematics Grade XI by Sukunda Pustak Bhawan

In this page, you can find the complete solutions of the second exercise of Review of Composition and Resolution of Vectors chapter from Basic Mathematics Grade XI book published and distributed by Sukunda Pustak Bhawan.

In the above-mentioned book, circle is the 13th chapter and has three exercises only. Out of which, this is the solution of the second exercise.

Check: Grade 11 Circle Exercise 1 Complete Solutions

Grade 11 Circle Exercise 1 Solutions | Basic Mathematics Grade XI by Sukunda Pustak Bhawan

Check: Basic Mathematics Grade 11 (Sukunda Publication) Guide:

Grade 11 Basic Mathematics by Sukunda Pustak Vawan Notes and Solutions | Nepal

Disclaimer:

Answers mentioned here are not solved by teachers. These are the solutions written by a student of Grade 11. Answers are all correct. However, the language or process of solving the questions might be informal and in examinations, you might have to add little more language and show more calculations than what has been done here. So, we highly encourage you to view these solutions as guide rather than just copying everything mentioned here.

1) Show that the following points are collinear.

$a) (1,-2,3), (2,3,04) and (0,-7,10)

Solution: If three points are collinear,

$ \left | \displaylines{ x_1 & y _ 1 & z_1 \\ x_2 & y_2 & z_2 \\ x_3 & y_3 & z _3} \right | = 0$

$\implies \left | \displaylines{ 1 & -2 & 3 \\ 2 & 3 & -4 \\ 0 & -7 & 10} \right | = 0$

$\implies 1 ( 30 - 28) + 2 (20) + 3(-14) = 0$

$implies 2 + 40 - 42 = 0$

$\implies 0 = 0$ which is true, hence, proved.