Geometry is the easiest portion of Mathematics in Class 10, if you exclude
the out theorem which comes for 5 marks. Other questions are very easy to
tackle and aren't much tricky.
Geometry is asked in all Groups i.e. Group A, Group B, Group C, and Group
D.
In Group A, it is asked for 1 mark (1 question).
In Group B, it is asked for 4 marks (2 questions).
In Group C, it is asked for 12 marks (3 questions).
In Group D, it is asked for 5 marks (1 question).
Let us move to the solutions of Area of Triangles and Quadrilaterals from
Geometry Chapter of Class 10.
Exercise 13.1
Also check Exercise 13.2 Solutions
General Section
Page 1 of 7
Page 2 of 7
Page 3 of 7
Page 4 of 7
Page 5 of 7
Page 6 of 7
Page 7 of 7
Creative Section
3 a) In the adjoining figure, ABCD and BCEF are
parallelograms, AE//BC. Prove that: parm.ABCD =
parm.BCEF.
3 b): In the figure alongside, QR//PS. Prove that ∆PQR
is equal to ∆QRS.
3 c) In the given figure, DX//AB. Prove that area of
triangle.ABX = 1/2 area of parallelogram.ABCD.
3 d) In the given figure, ABCD is a parallelogram.
X is any point within it. Prove that the sum of the
areas of traingle.XCD and triangle.XAB is equal to
half of the area of parallelogram.ABCD.
3 e) In the adjoining figure, triangles AMB and ANB
are standing on the same base AB and between the
same parallel lines AB and MN. Prove that area of
triangle.AOM = area of triangle.BON.
3 f) In the given figure, triangle.ABC and
parallelogram.MBCN are on the same base BC and
between the same parallels MN and BC. Prove that,
area of triangle.ABC = area of rectangle.APCN.
3 g) In the given parallelogram ABCD, X and Y
are any points on CD and AD respectively. Prove
that, area of triangle.AXB = area of
triangle.BYC.
3 h) In the adjoining parallelogram ABCD, A is
joined to any point E on BC. AE and DC produced
meet at E. Prove that, area of triangle.BEF =
area of triangle.CDE.
Correction: In the reason of statement
number 7, instead of writing "Whole part axiom", you should be writing "Remaining part of whole".
3 i) In the given figure, rectangle PQRS and
parallelogram AQRB on the same base QR and
between the same parallels PB and QR. Prove that
(i) triangle.PQA is congruent to triangle.SRB
and (ii) Area of rectangle PQRS = Area of
rectangle AQRB.
3 j) In the adjoining parallelogram ABCD,
PQ//AB and RS//BC. Prove that area of
parallelogram.ROPA = area of
parallelogram.OCSO.
3 k) In the given figure, ABCD is a
parallelogram. If M and N are any points on CD
and DA respectively, prove that triangle.AMB =
triangle.CDN + triangle.ANB.
3 l) In the given diagram, ABCD and PQRD are
two parallelograms. Prove that parm.ABCD =
parm.PQRD.
3 m) In the given figure, if AB//DC//EF, AD//BE
and AF//DE, prove that parm.DEFH = parm.ABCD.
4 a) In the given triangle ABC, P is any point on the median AD. Prove that triangle APB = triangle APC.
4 b) In the adjoining triangle ABC, P and Q are the mid-points of the sides AB and AC respectively and R be any point on BC. Prove that: area of triangle PQR = 1/4 area of triangle ABC.
4 c) In the figure, PQRS is a parallelogram. Q and S are joined to any point M on the diagonal PR. Prove that, area of triangle.PQM = area of triangle.PSM.
4 d) In the given figure, DE//BC. Prove that: (i) triangle BOD = triangle COE and (ii) triangle BAE = triangle CAD.
4 e) In the given figure, P is the mid-point of AB and Q is any point on the side BC. CR meets AB at R and CR//PQ. Prove that, area of triangle BQR = 1/2 area of triangle ABC.
4 f) The line drawn through the vertex C of the quadrilateral ABCD parallel to the diagonal DB meets AB produced at E. Prove that, area of quad. ABCD = area of triangle DAE.
4 g) In the given triangle ABC, two medians BE and CD are intersecting at O. Prove that, area of triangle BOC = area of quadrilateral ADOE.
4 h)
In the adjoining figure, it is given that AD//BC and BC//CE. Prove that, area of triangle.ABC = area of triangle.BDE.
4 i) In the given figure, BEST is a parallelogram. Diagonal BS is produced to point L. Prove that: triangle LST and triangle LSE are equal in area.
4 j) In the given figure, AD//BC. If the area of triangle ABE and triangle ACF are equal, then prove that EF // AC.
4 k) In the given figure, Ad//BE//GF and AB//DG//EF. If the area of parallelograms ABCD and CEFG are equal, then prove that DE // BG.
4 l) In the adjoining figure, PQRS and LQMN are two parallelograms of equal in area. Prove that LR // SN.
4 m) In the given triangle ABC, medians BN and Cm are intersected at O. Prove that: Area of triangle BOC = Area of quadrilateral AMON.
4 n) In the given figure, M is the mid-point of AE, then prove that area of triangle ABE is equal to the area of parallelogram ABCD.
4.
About vedanta EXCEL in MATHEMATICS Book 10
Author: Hukum Pd. Dahal
Editor: Tara Bahadur Magar
Vanasthali, Kathmandu, Nepal
+977-10-4382404, 01-4362082
vedantapublication@gmail.com
About this page:
Class 10 - Geometry - Area of Triangles and
Quadrilaterals- Solved Exercises | vedanta Excel in
Mathematics is a collection of the solutions related
to theorem proofs of figures related to the area of
triangles and quadrilaterals of geometry chapter for
Nepal's Secondary Education Examination (SEE)
appearing students.
#Class10
14 Comments
Can you post from no.4 (i)
ReplyDeletetoo??
Post all questions of no. 4
ReplyDeleteDo you have solns from no.1
DeletePost questions from qstn no.1
ReplyDeleteWe are extremely sorry sir. We have no plans of adding further more solutions of this page here in this blog. We are soon planning to shift to eLearn NEPAL. So, we are not really sure if the solution will be added any time sooner.
DeleteSir please give solution of 1 and 2 and 4 All solutions
ReplyDeleteWe have updated it for 1 and 2. We will try our best for question number 4.
DeleteSir provide solution of 1 all solution and 2 all solution without missing any question for our great future .
ReplyDeleteWe have got the complete solutions from question number 2. However, we have just one solution from question number 1. Hope you understand. Thank You.
Deleteelearn NEPAL looks good.
ReplyDeleteHello!! Can you please provide us geometry circle chapter solutions?
ReplyDeleteHere it is Geometry - Circle Solutions. Solutions are being updated!
DeleteIt really helped me to complete my assignment and to understand the way of solving the problems.. thank you so much for this page..
ReplyDeleteYou're Welcome
DeleteYou can let us know your questions in the comments section as well.